Team:Paris/Modeling/f2
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Exactly as for the binding of IPTG on LacR (see [[Team:Paris/Modeling/estimation#how_to_control_the_concentration_of_the_transcription_factor_.3F|TF concentration control]]), leading to a lowered inhibition of ''Plac'', aTc binds to TetR. So, after having determinated the Hill function [expr.''Ptet''] = ƒ2(TetR) = ƒ2aux(IPTG), we can study [expr.''Ptet''] = ƒ2ter([TetR],[aTc]), and determine by calcul [TetR<sub>active</sub>] = ƒ2bis(aTc) = f2<sup>-1</sup>([expr.''Ptet'']), to endly give an analytical expression of ƒ2ter = ƒ2οƒ2bis | Exactly as for the binding of IPTG on LacR (see [[Team:Paris/Modeling/estimation#how_to_control_the_concentration_of_the_transcription_factor_.3F|TF concentration control]]), leading to a lowered inhibition of ''Plac'', aTc binds to TetR. So, after having determinated the Hill function [expr.''Ptet''] = ƒ2(TetR) = ƒ2aux(IPTG), we can study [expr.''Ptet''] = ƒ2ter([TetR],[aTc]), and determine by calcul [TetR<sub>active</sub>] = ƒ2bis(aTc) = f2<sup>-1</sup>([expr.''Ptet'']), to endly give an analytical expression of ƒ2ter = ƒ2οƒ2bis | ||
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Otherwise, if we find in the litterature the dissociation constant of the reaction aTc + TetR⇄ aTc_TetR, we could determine by calculus the amount of free TetR, function of the expression of a known constitutive promoter before ''tetR'' and of the added aTc. In this way, we just have to study [expr.''Ptet''] = ƒ2(TetR<sub>free</sub>). | Otherwise, if we find in the litterature the dissociation constant of the reaction aTc + TetR⇄ aTc_TetR, we could determine by calculus the amount of free TetR, function of the expression of a known constitutive promoter before ''tetR'' and of the added aTc. In this way, we just have to study [expr.''Ptet''] = ƒ2(TetR<sub>free</sub>). | ||
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Revision as of 18:51, 12 August 2008
No particular strain.
Exactly as for the binding of IPTG on LacR (see TF concentration control), leading to a lowered inhibition of Plac, aTc binds to TetR. So, after having determinated the Hill function [expr.Ptet] = 2(TetR) = 2aux(IPTG), we can study [expr.Ptet] = 2ter([TetR],[aTc]), and determine by calcul [TetRactive] = 2bis(aTc) = f2-1([expr.Ptet]), to endly give an analytical expression of 2ter = 2ο2bis
Otherwise, if we find in the litterature the dissociation constant of the reaction aTc + TetR⇄ aTc_TetR, we could determine by calculus the amount of free TetR, function of the expression of a known constitutive promoter before tetR and of the added aTc. In this way, we just have to study [expr.Ptet] = 2(TetRfree).